r - converting hours:minutes with unevern column lengths - zeros -

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i trying convert data.frame amount of time in format hours:minutes.

i found post useful , simple code approach of using posixlt field type.

r: convert hours:minutes:seconds

however each column represents month's worth of days. columns uneven. when try code below following several other posts, zeros in 1 column fewer row values.

the code below. note when run, zeros feb has fewer data values in rows. 

rdf <- data.frame(jan=c("9:59","10:02","10:04"),               feb=c("9:59","10:02",""),               mar=c("9:59","10:02","10:04"),stringsasfactors = false)  (i in 1:3) {   res <- as.posixlt(paste(sys.date(), rdf[,i]))   rdf[,i] <- res$hour + res$min/60 }

thank suggestions fix issue. i'm open more efficient approach well. best, leah

you try using package lubridate. here converting data row row hour-minute format (using hm), extracting hours, , adding minutes divided 60:

library(lubridate)  rdf[] <- lapply(rdf, function(x){hm(x)$hour + hm(x)$minute/60})          jan       feb       mar 1  9.983333  9.983333  9.983333 2 10.033333 10.033333 10.033333 3 10.066667        na 10.066667

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