android - ionic overwrite active element in css -

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i tried many example answer stackoveflow no 1 useful in application please me solve problem thank

sidemenu:

<ion-list class="side" id="sidemenuactive">   <ion-item menu-close href="#/sidemenu/home">     <i class="icon ion-ios-home-outline"></i>&nbsp; home   </ion-item>   <ion-item menu-close href="#/sidemenu/mydeal">     <i class="icon ion-compose"></i>&nbsp; profile   </ion-item> </ion-list>

css:

#sidemenuactive .active{background: #000000 !important;}

the ion-item directive injects "a" element in content. element need use when define styles.

<ion-list>     <ion-item ui-sref=".item1" ui-sref-active="active">item 1</ion-item>     <ion-item ui-sref=".item2" ui-sref-active="active">item 2</ion-item> </ion-list>

css:

ion-list ion-item.active  {     background-color: #000 !important;  }

nb: have add (at place) "active" class active ion-item. did using directive ui-sref-active. please mind ionic use angular-ui router , you'd better use ui-sref instead of href links. ui-sref allows directly give name of route parameter (thus, don't have handle uri).


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