c++ - Pass a __thiscall to a function typedef -

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• how can pass class member function callback? 8 answers

i don't know how word this, i'll try best explain in code:

typedef void( *examplefn )( pvoid p1, pvoid p2, pvoid p3 );  struct example {     void examplefunction( pvoid p1, pvoid p2, pvoid p3 )     {         // example's members     } };  example example; examplefn examplefn = example.examplefunction; 

so, error:

error c2440 '=': cannot convert 'void (__thiscall example::* )(pvoid,pvoid,pvoid)' 'examplefn' 

i understand problem, example::examplefunction __thiscall , examplefn not, how can go this?

how have example object examplefn-like function in can use object's members?

you need define youre function-pointer correctly. it's member-function pointer, needs this:

typedef void(example::*examplefn )( pvoid p1, pvoid p2, pvoid p3 ); 

the __thiscall call-convention of member-functions, that's set automatically.

you defined pointer plain-function doesn't work. doesn't concern call-convetion really.