python - How to execfile an independent .py and continue on to next line of code in the original .py? -

i have 2 python files: 'old.py' , 'new.py'. execute 'new.py' 'old.py' using execfile("new.py"). however, rather waiting 'new.py' finish program before moving next line in 'old.py', both scripts continue independently (i.e., 'old.py' moves line after execfile('new.py') command immediately.

for instance, if 'new.py' takes 48 seconds complete program in entirety, , 'old.py' reads:

execfile("new.py") print 2+2 

i "4" printed immediately, rather 48 seconds later.

how recommend doing this?

thank sharing knowledge , expertise.

you want utilize subprocess.popen. open process in separate process.

# old.py - make sure it's chmod +x #!/usr/bin/python import time  time.sleep(48) 

# new.py  #!/usr/bin/python import subprocess  subprocess.popen(["./old.py"]) print(2+2) 

>>> python new.py  4 >>> ps   pid tty          time cmd  2495 pts/17   00:00:00 bash  2696 pts/17   00:00:00 old.py  2697 pts/17   00:00:00 ps