python - Read a string of 1's and 0's. Count numbers of successive 1's and number of successive 0's, until the end -

read string of 1's , 0's. count numbers of successive 1's , number of successive 0's, until end.

for example,

s = "10001110000111" 

output should be:

1 1's 3 0's 3 1's 4 0's 3 1's 

i need approaching using string functions (no find function), , while/for loops.

i have this:

mystring = input("please enter string of 0s , 1s: ") zerocount = 0 onecount = 0 index = 0  while index < (len(mystring) -1):     if mystring[index] == "0":         zerocount += 1         if mystring[index +1] == "1":             zerocount = 0     elif mystring[index] == "1":         onecount += 1         if mystring[index +1] == "0":             onecount = 0     index += 1 

what doing wrong?

this quite similar what's called 'run length encoding' has nice entry on rosettacode.org

def encode(input_string):     count = 1     prev = ''     lst = []     character in input_string:         if character != prev:             if prev:                 entry = (prev,count)                 lst.append(entry)                 #print lst             count = 1             prev = character         else:             count += 1     else:         entry = (character,count)         lst.append(entry)     return lst   def decode(lst):     q = ""     character, count in lst:         q += character * count     return q  #method call encode("aaaaahhhhhhmmmmmmmuiiiiiiiaaaaaa") decode([('a', 5), ('h', 6), ('m', 7), ('u', 1), ('i', 7), ('a', 6)]) 

i think you'll able take , modify bit want.