I want to print pattern of numbers using c program -

if n=3,the output

1*2*3  7*8*9  4*5*6 

if n=5,the output

1*2*3*4*5  11*12*13*14*15  21*22*23*24*25  16*17*18*19*20  6*7*8*9*10 

code:

int i,j,a[50][50],k=1,m=0; for(i=0;i<n;i+=2) {     for(j=0;j<n;j++) {         a[i][j]=k; k++;     }     printf("\n"); } m=k; for(i=1;i<=n;i+=2) {     for(j=0;j<n;j++) {         a[i][j]=m;         m++;     }     printf("\n"); } for(i=0;i<n;i++) {     for(j=0;j<n;j++) {         printf("%d",a[i][j]);     }     printf("\n"); } 

i not in c language, think you. please have look, , can making change if syntax error occurs logic clear.

#include <stdio.h> #include <math.h>  void printoutput(int n){  int k = ceil(n/2); int m =1; int j =1; int l =k; int i; int b; for(i=1;i<=n;i++){  for(b=m;b<=m+n;b++){  printf(b); } printf("\n");   if(i<k){        j= (2*j);     m =n*j+1;   } else{     int z = n-i-1;      m= n+1 +n*(2)*z;     l =z-2;    } } }  void main(){     int input;     printf("enter value : ");     scanf(" %d",&input);     printoutput(input); }