c++ - How can I quickly printf 2 dimensional array of chars made of pointers to pointers without using a loop? -

i'm making ascii game , need performance, decided go printf(). there problem, designed char array multidimensional char ** array, , printing outputs garbage of memory instead of data. know it's possible print loop performance rapidly drops way. need printf static array[][]. there way?

i did example of working , notworking array. need printf() work nonworking array.

edit: using visual studio 2015 on win 10, , yeah, tested performance , cout slower printf (but don't know why happening)

#include <iostream> #include <cstdio>  int main() {     const int x_size = 40;     const int y_size = 20;      char works[y_size][x_size];     char ** notworking;      notworking = new char*[y_size];     (int = 0; < y_size; i++) {         notworking[i] = new char[x_size];     }      (int = 0; < y_size; i++) {         (int j = 0; j < x_size; j++) {             works[i][j] = '#';             notworking[i][j] = '#';         }         works[i][x_size-1] = '\n';         notworking[i][x_size - 1] = '\n';     }     works[y_size-1][x_size-1] = '\0';     notworking[y_size-1][x_size-1] = '\0';      printf("%s\n\n", works);     printf("%s\n\n", notworking);      system("pause"); } 

note: think make kind of buffer or static array copying , displaying data, wonder if can done without it.

if print 2d structure printf without loop, need present printf contiguous one-dimension c string. since game needs access string 2d structure, make array of pointers flat structure this:

array of pointers partitions buffer use 2d structure, while buffer can printed printf because contiguous c string.

here same structure in code:

// x_size+1 '\n's; overall +1 '\0' char buffer[y_size*(x_size+1)+1]; char *array[y_size]; // setup buffer , array (int r = 0 ; r != y_size ; r++) {     array[r] = &buffer[r*(x_size+1)];     (int c = 0 ; c != x_size ; c++) {         array[r][c] = '#';     }     array[r][x_size] = '\n'; } buffer[y_size*(x_size+1)] = '\0'; printf("%s\n", buffer); 

demo.