c++ - Passing pointer to any member function as class template argument -

template<typename t, typename m, m method> class proxyobject { public:      template<typename... args>     void invoke (t& object, _in_ args&&... a)     {         (void)(object.*method)(std::forward<args>(a)...);     } };  class object { public:      int mymethod (int val)     {         wcout << l"hello!" << endl;         return val;     } };   int wmain () {     object myobj;     proxyobject<object, decltype(&object::mymethod), &object::mymethod> obj;      obj.invoke(myobj, 10);      return 0; } 

the decltype(&object::mymethod) seems redundant in definition of obj. there way make proxyobject automatically infer type of pointer-to-member-function being passed, can define obj follows:

proxyobject<object, &object::mymethod> obj; 

i think it's impossible class template, because have specify member function type explicitly.

template function lot argument deduction:

template<typename t, typename m, typename... args> void invoke (t& object, m method, args&&... a) {     (void)(object.*method)(std::forward<args>(a)...); } 

then

invoke(myobj, &object::mymethod, 10); 

live