url - How to handle links containing space between them in Python -
i trying extract links webpage , open them in web browser. python program able extract links, links have spaces between them cannot open using request module . for example example.com/a, b c not open using request module. if convert example.com/a,%20b%20c open. there simple way in python fill spaces %20 ? `http://example.com/a, b c` ---> `http://example.com/a,%20b%20c` i want convert links have spaces between them above format. urlencode takes dictionary, example: >>> urllib.urlencode({'test':'param'}) 'test=param'` you need this: import urllib import urlparse def url_fix(s, charset='utf-8'): if isinstance(s, unicode): s = s.encode(charset, 'ignore') scheme, netloc, path, qs, anchor = urlparse.urlsplit(s) path = urllib.quote(path, '/%') qs = urllib.quote_plus(qs, ':&=') return urlparse.urlunsplit((scheme, netloc, path, qs, anchor)) then: >>>url_...