url - How to handle links containing space between them in Python -

i trying extract links webpage , open them in web browser. python program able extract links, links have spaces between them cannot open using request module.

for example example.com/a, b c not open using request module. if convert example.com/a,%20b%20c open. there simple way in python fill spaces %20 ?

`http://example.com/a, b c` ---> `http://example.com/a,%20b%20c` 

i want convert links have spaces between them above format.

urlencode takes dictionary, example:

>>> urllib.urlencode({'test':'param'}) 'test=param'` 

you need this:

import urllib import urlparse  def url_fix(s, charset='utf-8'):     if isinstance(s, unicode):         s = s.encode(charset, 'ignore')     scheme, netloc, path, qs, anchor = urlparse.urlsplit(s)     path = urllib.quote(path, '/%')     qs = urllib.quote_plus(qs, ':&=')     return urlparse.urlunsplit((scheme, netloc, path, qs, anchor)) 

then:

>>>url_fix('http://example.com/a, b c')     'http://example.com/a%2c%20b%20c' 

taken how can normalize url in python